Integrand size = 11, antiderivative size = 37 \[ \int \frac {(a+b x)^3}{x^4} \, dx=-\frac {a^3}{3 x^3}-\frac {3 a^2 b}{2 x^2}-\frac {3 a b^2}{x}+b^3 \log (x) \]
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Time = 0.01 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {45} \[ \int \frac {(a+b x)^3}{x^4} \, dx=-\frac {a^3}{3 x^3}-\frac {3 a^2 b}{2 x^2}-\frac {3 a b^2}{x}+b^3 \log (x) \]
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Rule 45
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {a^3}{x^4}+\frac {3 a^2 b}{x^3}+\frac {3 a b^2}{x^2}+\frac {b^3}{x}\right ) \, dx \\ & = -\frac {a^3}{3 x^3}-\frac {3 a^2 b}{2 x^2}-\frac {3 a b^2}{x}+b^3 \log (x) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.00 \[ \int \frac {(a+b x)^3}{x^4} \, dx=-\frac {a^3}{3 x^3}-\frac {3 a^2 b}{2 x^2}-\frac {3 a b^2}{x}+b^3 \log (x) \]
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Time = 0.17 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.92
method | result | size |
default | \(-\frac {a^{3}}{3 x^{3}}-\frac {3 a^{2} b}{2 x^{2}}-\frac {3 a \,b^{2}}{x}+b^{3} \ln \left (x \right )\) | \(34\) |
norman | \(\frac {-\frac {1}{3} a^{3}-3 a \,b^{2} x^{2}-\frac {3}{2} a^{2} b x}{x^{3}}+b^{3} \ln \left (x \right )\) | \(34\) |
risch | \(\frac {-\frac {1}{3} a^{3}-3 a \,b^{2} x^{2}-\frac {3}{2} a^{2} b x}{x^{3}}+b^{3} \ln \left (x \right )\) | \(34\) |
parallelrisch | \(\frac {6 b^{3} \ln \left (x \right ) x^{3}-18 a \,b^{2} x^{2}-9 a^{2} b x -2 a^{3}}{6 x^{3}}\) | \(38\) |
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Time = 0.21 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.00 \[ \int \frac {(a+b x)^3}{x^4} \, dx=\frac {6 \, b^{3} x^{3} \log \left (x\right ) - 18 \, a b^{2} x^{2} - 9 \, a^{2} b x - 2 \, a^{3}}{6 \, x^{3}} \]
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Time = 0.11 (sec) , antiderivative size = 36, normalized size of antiderivative = 0.97 \[ \int \frac {(a+b x)^3}{x^4} \, dx=b^{3} \log {\left (x \right )} + \frac {- 2 a^{3} - 9 a^{2} b x - 18 a b^{2} x^{2}}{6 x^{3}} \]
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Time = 0.20 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.92 \[ \int \frac {(a+b x)^3}{x^4} \, dx=b^{3} \log \left (x\right ) - \frac {18 \, a b^{2} x^{2} + 9 \, a^{2} b x + 2 \, a^{3}}{6 \, x^{3}} \]
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Time = 0.30 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.95 \[ \int \frac {(a+b x)^3}{x^4} \, dx=b^{3} \log \left ({\left | x \right |}\right ) - \frac {18 \, a b^{2} x^{2} + 9 \, a^{2} b x + 2 \, a^{3}}{6 \, x^{3}} \]
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Time = 0.05 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.92 \[ \int \frac {(a+b x)^3}{x^4} \, dx=b^3\,\ln \left (x\right )-\frac {\frac {a^3}{3}+\frac {3\,a^2\,b\,x}{2}+3\,a\,b^2\,x^2}{x^3} \]
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